Amika Interview Questions, Process, and Tips

Ques:- A train 100 m long crosses a platform 125 m long in 15 sec; find the speed of the train?
Recent Answer : Added by GAURAV WAGHELA On 2022-03-09 16:35:13:

1km is equal to 1000 meter
Therefore 225 meter is how many km
Then we have to cross multiply
1km – 1000 meter
? – 225 meter
0.225 km
Then we have to apply formula
Speed = Distance/Time
Speed = 0.225/12 sec
= 0.01875×3600sec
= 67.5
Therefore speed of train is = 67.5

Ques:- Find LCM of 18 and 27 .
Ques:- Why are you interested in oour compnay ?
Ques:- A banana plantation is located next to a desert. The plantation owner has 3000 bananas that he wants to transport to the market by camel, across a 1000 kilometer stretch of desert. The owner has only one camel, which carries a maximum of 1000 bananas at any moment in time, and eats one banana every kilometre it travels. What is the largest number of bananas that can be delivered at the market?
Recent Answer : Added by Dinesh Pandi On 2021-07-16 13:55:08:

there will be no banana left

Ques:- A taxi driver was going the wrong way on a one-way road. A traffic police officer noticed him but instead of stopping him or fine him, he let the driver go. Why do you think that happened?
Ques:- Why do you want to switch to our company?
Ques:- Use three adjectives to describe yourself?
Ques:- Tell of a time you made a mistake and how you dealt with it?
Ques:- The price of an article is cut by 20%. To restore it to the Former value, the new price must be increased by
A. 20%
B. 24%
C. 25%
D. 28%
Recent Answer : Added by Aayush Lodha On 2022-03-09 16:31:45:

LET ACTUAL PRICE BE 100 RS(FOR CONVINIENCE)
THEREFORE IF PRICE IS CUT BY 20%
THEREFORE NEW PRICE=100-20=80 RS
THEREFORE WE NEED TO ADD X% TO 80 RS TO MAKE IT 20 RS AND ADD IT TO 80 TO MAKE IT 100RS
THEREFORE, 80X/100 = 20
I.E. 4X/5=20
THEREFORE x=20*5/4
=5*5
=25
HENCE 25% OF PRICE SHOULD BE ADDED TO MAKE THE PRICE EQUAL TO THE ACTUAL PRICE.

Ques:- What are the steps that you will take for the development of the company?
Ques:- Family and other people
Ques:- Four couples sit around a circular table in a party. Every husband sits to the right of his wife. P, Q, R and S are husbands and T, U, V and W are wives. Q – U and R – V are two married couples. S does not sit next to V. T sits to the left of P, who sits opposite S. If every husband interchange his position with the person sitting opposite to him, then who sits between S and R?
Recent Answer : Added by Nandakumar Athiseshan On 2022-08-14 16:33:45:

P Q R S

TP -> UQ -> RV -> SW

Answers-

U sits opposite to S

Q sits in between S and R (after interchange)

Ques:- What are examples of interview answers that ask about attention to detail?
Recent Answer : Added by Anam Rana On 2022-05-08 20:56:17:

I will reading IPad questions and Awsome

Ques:- How am I an Ideal candidate for this post
Ques:- Infosys campus ques…u drive a car,nmb of d car is KA17M8719. it leaves at10:26am frm davanager to bangalor which is264km away at a speed of 95km/hrCar reachs bangalor at 4:18pm. nw tel me wat is d date of birth of drvr
Ques:- A salt manufacturing company produced a total of 5000 tonnes of salt in January of a particular year. Starting from February its production increased by 100 tonnes every month over the previous months until the end of the year. Find its average monthly production for that year?
Recent Answer : Added by albin On 2021-03-25 16:51:46:

516 tones

Ques:- How much experience you have as quality control Engineer?
Ques:- What was your last profile and elaborate it?
Recent Answer : Added by senorina On 2021-10-22 09:13:08:

accountant trainee at thenational board of accountants and auditors

Ques:- x==2+2^(2/3)+2^(1/3) .Then what is the value of x^3-6X^2+x ? here X^Y indicates X to the power of Y.
Recent Answer : Added by Admin On 2020-05-17 12:04:34:

(x-2)^3==x^3-6x^2+12x-8
(x-2)^3==(2^(2/3)+2^(1/3))^3
therefore,by solving
Ans: x^3-6x^2+x== -8-5*2^(2/3)-5*2^(1/3)

Ques:- 1/3 of girls , 1/2 of boys go to canteen .What factor and total number of classmates go to canteen.
Ques:- The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder. What is the smaller number?
Recent Answer : Added by Priya On 2022-05-17 09:06:45:

270

Ques:- Would you like to work overtime or odd hours?
Ques:- Do your SWOT analysis
Ques:- A gardener wants to plant trees in his garden in such a way that the number of trees in each row should be the same. If there are 4 rows or 5 rows or 6 rows, then no tree will be left. Find the least number of trees required.
Recent Answer : Added by Hemant On 2021-08-10 09:39:24:

Total 60 trees
4 rows each with 15 trees
5 rows each with 12 trees
6 rows each with 10 trees

Ques:- TELL ABOUT YOUR SELF BRIFLY
Ques:- In order to obtain an income of Rs. 650 from 10% stock at Rs. 96, one must make an investment of?
Ques:- The sum of the square of the three consecutive even natural numbers is 1460. Evaluate the numbers?
Recent Answer : Added by shraddha On 2022-05-17 09:06:40:

let square be x (squares are 4 sides)
i.e., X+X+X+X=4X
4X+3=1460
4X=1460-3
4X=1457
X=364.25

Ques:- Why this company will choose you?
Ques:- In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 600 m?
Recent Answer : Added by Kristi Bardhan On 2022-09-02 17:04:02:

When A runs 1000 meters, B runs 900 meters and when B runs 800 meters, C runs 700 meters.

Therefore, when B runs 900 meters, the distance that C runs = (900 x 700)/800 = 6300/8 = 787.5 meters.

So, in a race of 1000 meters, A beats C by (1000 – 787.5) = 212.5 meters to C.

So, in a race of 600 meters, the number of meters by Which A beats C = (600 x 212.5)/1000 = 127.5 meters.

Ques:- The sum of five consecutive even numbers of set x is 440. Find the sum of a different set of five consecutive integers whose second least number is 121 less than double the least number of set x?

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Devendra Bhardwaj With a decade of experience as a Job Hiring Expert, I am a results-driven professional dedicated to elevating recruitment strategies. My expertise lies in navigating the dynamic landscape of talent acquisition, employing innovative approaches to attract, assess, and secure top-tier candidates. I excel in optimizing hiring processes, leveraging cutting-edge technologies, and fostering collaborative relationships with stakeholders. A keen understanding of industry trends allows me to stay ahead, ensuring a competitive edge in securing the best talent for your organization. I am passionate about connecting the right people with the right opportunities and thrive in creating impactful, streamlined recruitment solutions.

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