1!=1
2!=2×1=2
3!=3x2x1=6
4!=4x3x2x1=24
5!=5x4x3x2x1=120
6!=6x5x4x3x2x1=720
The answer is 120.
1×2×…100=100!
Number of zeros in product of n numbers =[5n]+[52n]+[53n]+…
Number of zeros in product of 100 numbers =[5100]+[52100]+[53100]
where [.] is greatest integer function
=[20]+[4]+[0.8]=20+4=24
es, of course, there are a lot of people who start their careers with small things but after a few years, they grow themselves and get into better places. All you have to do is learn the skills of your desired domain while working on the other part and then use that to get a job in your desired place.
For example, consider you are an engineer and worked in a firm where you worked as a sales executive but you want to work as an IT professional in any IT firm then while working as a sales executive you can try to learn some coding languages like C or Java and after getting a good command on that you can apply for a job of developer or any IT professional. The only disadvantage is that your sales experience will have nothing to contribute to your IT job so you’ll be hired and paid as a fresher only.
I hope this helps you.
cube root of 5 is 125 so 128 is nearer to 125 and hence 5+5+5=15 and the nearest answer amongst options is 17 so 17 is correct answer:) yipppy……..
(a) 29.12 (actual)
first year rate of paper (inflation rate) : 25 + 25 *
6.5/100 = 26.625
paper rate in first year is 1.5 % more . ..thr4
inflated cost in 1 yr = 26.625 + 1.5 / 100 * 26.625 =
27.024.
second year : 27.024 + 27.024 * 6.5 / 100 = 28.78
paper cost : 1.5 /100 * 28.78 + 28.78 = 29.12 ( approx..)
(1) There exists a smaller natural number.
(2) There exists a largest natural number.
(3) Between two natural numbers, there is always a natural number.
Which of the above statement is/are correct?
B
125, 123, 120, 115, 108, 100, 84
b
Let the numbers be x and x + 2.
Then, (x + 2)2 – x2 = 84
⇒ 4x + 4 = 84
⇒ 4x = 80
⇒ x = 20.
∴ The required sum
= x + (x + 2)
= 2x + 2
= 42
500 ways