Fermanagh &Omagh Interview Questions, Process, and Tips

speed of the train respect to man
= (63 – 3) km/hr
= 60 km/hr
= 60 * 1000 / 3600 m/sec
= 50/3 m/sec

time
= distance/speed
= 500 * 3/ 50
= 30 sec

Let 10’splace digit is x and unit’s place digit y

First milestone : 10x+y
Second milestone : 10y+x
Third milestone: 100x+y

Since the speed is uniform so
Distance covered in first Hr = Distance covered in Second Hr
(10y+x)-(10x+y) = (100x+y)-(10y+x)
After solving, we get —-> y=6x but since x and y are digits so only possible combination is x=1 and y=6,
So average speed = 45 KM/HR

31

Let\: the\: total\: price \: be\: Rs. X\: then,

B= 2x/7 & A= \left ( x-2 \right )/7

So, A:B = 5x/7 : 2x/7 = 5 : 2

Let \: B’s \: capital\; be\: Rs.Y\: then\: \left ( 16000\ast 8 \right )/4y= 5/2

=> (16000\ast 8\ast 2)/(4\ast 5) = y

=> y = Rs. 12800

8 games They played
A own 3 games = 18 Rs
B loss 3 Rs and own 1 games i,e 9(A own 3 Games)-6(B own
1 game)=3
c own 12 Rs and loss 4 games(A own 3+b own 1) and own 4
games i.e 24(own)-12(loss)
so totally A own 3 games
B own 1 game
c own 4 games
=8

4 years

let the no be x
then given that the difference between the number and 3/5th
of the number is 50
therefor , x-3/5x=50
2x=250
x=125 is the answer

240 m

Reduction of 40% or 4/10th in price of bananas will lead to an increase of 4/(10 – 4) = 2/3rd part in quantity if expenditure is constant.
If original quantity is q, then :
2q/3 = 64
=> q = 64 x 3/2 = 96 = 8 dozens.
=> Original price per dozen = 40/8 = Rs 5

The 3-digit number can be written as the sequence [n, 2n, 3n]
n = 1 → [1, 2, 3] → valid
n = 2 → [2, 4, 6] → valid
n = 3 → [3, 6, 9] → valid

n = 4 → [4, 8, 12] is not valid because this would lead to a 4-digit number
any value of n > 4 would also produce invalid answer

Answer: Three numbers: {123, 246, 369}

CPNCBZ