Ques:- Find the smallest number which when divided by 13 and 16 leaves respective remainders of 2 and 5.
Recent Answer : Added by Abhishek Gupta On 2022-08-24 17:03:32:
Let ‘N’ is the smallest number which divided by 13 and 16 leaves respective remainders of 2 and 5.
Required number = (LCM of 13 and 16) – (common difference of divisors and remainders)
= (208) – (11) = 197.
Ques:- Number Series 40,42,39,44,38,46,?
Recent Answer : Added by Admin On 2020-05-17 12:01:22:
37
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Ques:- 5 men and 12 boys finish a piece of work in 4 days, 7 men and 6 boys do it in 5 days. The ratio between the efficiencies of a man and boy is?
Recent Answer : Added by Upendra Dwivedi On 2022-08-14 16:33:18:
6/5
Ques:- Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
Recent Answer : Added by PuusinD On 2022-08-14 16:36:00:
10 a.m.
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Ques:- 98th term of the infinite series 1, 2, 3, 4, 1, 2, 3, 4, 1, 2, …… is
A. 1
B. 2
C. 3
D. 4
Recent Answer : Added by Hemlata vasava On 2022-08-14 16:39:47:
A, b
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Ques:- The three boxes 1,2,3 has values resp. AB,BC,AC Get 2A(B+C) +AC-2C(A-B)in Box 1 using only addition in 3 steps.
Recent Answer : Added by Admin On 2020-05-17 12:02:03:
GIVEN: 2A(B+C)+AC-2C(A-B)
THEREFORE 2AB+2AC+AC-2AC+2BC
2AB+AC+2BC
2(AB+BC)+AC
LET b1=AB b2=BC b3=AC
STEP1: b1 = b1+b2
so b1 = AB+BC
THEREFORE
NOW: b1 = AB+BC b2 = BC b3 = AC
STEP 2: b3 = b1+b3
so b3 = AB+BC+AC
THEREFORE
NOW: b1 = AB+BC b2 = BC b3 = AB+BC+AC
STEP3:
NOW: b1 = b1+b3
so b1 = AB+BC+AB+BC+AC
=2(AB+BC)+ AC
AB BC AC
STEP1 AB+BC BC AC
STEP2 AC BC AB+BC+AC
STEP3 AB+BC+AB+BC+AC BC AB+BC+AC
i.e 2(AB+BC)+AC BC AB+BC+AC
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Recent Answer : Added by tej On 2022-08-14 16:31:01:
10m/sec
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10
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Ques:- Number Series 11,14,12,15,13,16,?
Recent Answer : Added by Admin On 2020-05-17 11:59:56:
11 14
12 15
13 16
=======
14 17
the answers is 14
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Recent Answer : Added by Kom On 2021-08-06 04:58:03:
Actually
carrots=> $12
celery => $3
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Ques:- Four bells begin to toll together respectively at the intervals of 8, 10, 12 and 16 seconds. After how many seconds will they toll together again?
Let ‘N’ is the smallest number which divided by 13 and 16 leaves respective remainders of 2 and 5.
Required number = (LCM of 13 and 16) – (common difference of divisors and remainders)
= (208) – (11) = 197.