a. (x+y)'=x'.y' b. (x'+y')'=x.y
c. (x'.y')'=x+y d. (x'+y')'=x'.y'
GIVEN: 2A(B+C)+AC-2C(A-B)
THEREFORE 2AB+2AC+AC-2AC+2BC
2AB+AC+2BC
2(AB+BC)+AC
LET b1=AB b2=BC b3=AC
STEP1: b1 = b1+b2
so b1 = AB+BC
THEREFORE
NOW: b1 = AB+BC b2 = BC b3 = AC
STEP 2: b3 = b1+b3
so b3 = AB+BC+AC
THEREFORE
NOW: b1 = AB+BC b2 = BC b3 = AB+BC+AC
STEP3:
NOW: b1 = b1+b3
so b1 = AB+BC+AB+BC+AC
=2(AB+BC)+ AC
AB BC AC
STEP1 AB+BC BC AC
STEP2 AC BC AB+BC+AC
STEP3 AB+BC+AB+BC+AC BC AB+BC+AC
i.e 2(AB+BC)+AC BC AB+BC+AC
Either 4 or (-)4
a
A, b
In 5liter alchol is 20%
In 1liter alchol is0.2÷5=0.04liter
Taken out 2liter solution =3liter solution
Alchol present 3×0.04=0.12liter
7liter water alhol present=0.12liter
12%
P1/P2 = C1*T1/ C2*T2
where P1 = Partner 1’s Profit.
C1 = Partner 1’s Capital.
T1 = Time period for which Partner 1 contributed his capital.
P2 = Partner 2’s Profit.
C2 = Partner 2’s Capital.
T2 = Time period for which Partner 2 contributed his capital
6000/3000= 20,000*6/x*12
x=5000
a/g
Let Suvarna, Tara, Uma and Vibha be S,T,U,V respectively
initially in the beginning each persons share be
V = x U = y T = z
S = w = (x+y+z+32) Reason: She has to double others share, so she should have each and everyone’s share and still should be left out with 32
after 1st Round of game
S loses and is out with 32 and doubles the others share
V = 2x U = 2y T = 2z
After 2nd Round of game
T loses and is out with 32 and doubles the others share
V = 4x U = 4y
This means T had 2z = 2x + 2y + 32
After 3rd round of game
U looses and is out with 32 and doubles others share
V = 8x
This means U initially has 4y = 4x + 32
In the end V = 8x = 32
Solving this we get x = 4, y = 12, z = 32 and w = 80
There fore Suvarna had highest share in the beginning
Alcohol content from
2 l of A (62.5%) : 1.35L
4L of B (87.5%) : 3.50L
Total Acohol content in 6 L : 4.85L or 80.8%
Answer: 1 / 3
Lets say each brand had 16 laptops
So Sold : A = 3 , B= 1 and C = 12 , total sold: 16 ,
Since each brand has 16 , total = 48
so 16/ 48 = 1/3 is the sold fraction
8 is the answer
b’coz no two have the same age
8+6+5+4+3=26
600
C