Ques:- In a grass field, If there are 40 cows, they could eat for 40 days. If there are 30 cows, they could eat for 60 days. Than if 20 cows, How much day they could eat?
A. 60
B. 80
C. 55
D. 50
Recent Answer : Added by Admin On 2020-05-17 12:05:48:
40
40
30
60
– 10 cows
+ 20 days
if 40 cows can eat for forty days
then 20 cows can eat for 80 days
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Ques:- A train running at the speed of 60 km/hr crosses a pole in 9 seconds. Find the length of the train?
Recent Answer : Added by Admin On 2022-09-29 15:10:14:
Time =9 seconds
Speed =(60×518) m/sec=(503)m/sec
∴ Speed =DistanceTime
Length of the train (Distance) = (Speed × Time) = (503×9) m=150 m.
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Recent Answer : Added by jeevi sireesha On 2022-11-29 17:07:02:
my best friend name is chandrakala. she is try to job.
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Recent Answer : Added by Thomas On 2021-11-18 17:16:33:
Very exited
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Ques:- What are ActiveX Controls
Recent Answer : Added by Admin On 2020-05-17 12:04:04:
these components can be used to add specialized
functionality, such as animation or pop-up menus, to Web
pages, desktop applications, and software development tools.
Ques:- A starts from a place at 11.00 am and travels at a speed of 4 kmph , B starts at 1.00 pm and travels with speeds of 1 kmph for 1 hr , 2 kmph for the next hr , 3 kmph for the next hr and so on. At wht time will B catch up with A ?
Recent Answer : Added by DK BOSS On 2021-07-17 06:18:40:
the answer is At 9:48 PM
At 1:00 pm the difference between A & B = 8 km
after 2:00 pm ………………. = 11 km (as B’s speed
is 1 and A’s 4 km, then eqv speed=(4-1)=3 km)
After 3:00………………….. = 13 km (as B’s speed 2 km)
After 4:00………………….. = 14 km
after 5:00………………….. = 14 km (A’s speed= B’s
speed)
after 6:00………………….. = 13 km
after 7:00………………….. = 11 km
after 8:00………………….. = 8 km
after 9:00………………….. = 4 km
and now the eqv speed is= (9-4) =5 km/hr;
and the renaming distance is 4 km;
then, time=(60*4)/5=48 min;
then the meeting time is=9:00+48 min=9:48 pm;
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Recent Answer : Added by Aditya On 2021-08-09 01:51:44:
17:3
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Ques:- Four sisters- Suvarna, Tara, Uma and Vibha are playing a game such that the loser doubles the money of each of the other players from her share. They played four games and each sister lost one game in alphabetical order. At the end of fourth game, each sister has Rs. 32. Who started with the highest amount?
Recent Answer : Added by Vinay K On 2022-09-24 14:33:35:
Let Suvarna, Tara, Uma and Vibha be S,T,U,V respectively
initially in the beginning each persons share be
V = x U = y T = z
S = w = (x+y+z+32) Reason: She has to double others share, so she should have each and everyone’s share and still should be left out with 32
after 1st Round of game
S loses and is out with 32 and doubles the others share
V = 2x U = 2y T = 2z
After 2nd Round of game
T loses and is out with 32 and doubles the others share
V = 4x U = 4y
This means T had 2z = 2x + 2y + 32
After 3rd round of game
U looses and is out with 32 and doubles others share
V = 8x
This means U initially has 4y = 4x + 32
In the end V = 8x = 32
Solving this we get x = 4, y = 12, z = 32 and w = 80
There fore Suvarna had highest share in the beginning
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Recent Answer : Added by Shaikot On 2021-06-23 17:55:45:
(10×1000) / (2×3.1416×1.75) = 909 times (about)
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40
40
30
60
– 10 cows
+ 20 days
if 40 cows can eat for forty days
then 20 cows can eat for 80 days