Ques:- In a Park, N persons stand on the circumference of a circle at distinct points. Each possible pair of persons, not standing next to each other, sings a two-minute song ? one pair immediately after the other. If the total time taken for singing is 28 minutes, what is N?
Recent Answer : Added by Admin On 2022-09-29 18:42:28:
Total number of pairs is NC2^{N}C_2NC2. Number of pairs standing next to each other = N. Therefore, number of pairs in question = NC2^{N}C_2NC2 – N = 28/2 = 14. If N = 7,
7C2 – 7 = 21 – 7 = 14….
N =7
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Ques:- 1) In a club there are certain no. of males and females. If 15 females are absent then no. of males will be twice that of females. If 45 males are absent then female strength will be 5 times that of males. Find no. of males actually present.
Recent Answer : Added by Admin On 2020-05-17 12:01:55:
Let the number of males be given the name M.
Let the number of females be given the name F.
If 15 females are absent, then M will be twice that of
present females.
This means that M = 2 * (F – 15)
M = 2 * F – 30.
or 2 * F – M = 30.
Now if in addition to the 15 females being absent, we also
have 45 males being absent,
then this gives the equation,
(F – 15) = 5 * (M – 45)
which simplifies to
F – 15 = 5 * M – 225
5 * M – F = 210
Pulling the equations together, we get
5 * M – F = 210
-M + 2 * F = 30
Multiply the first equation by 2, and keep the second
equation as is.
10 * M – 2 * F = 420
– M + 2 * F = 30
Add the equations.
9 * M = 450
M = 50
Verify answer.
Calculate F
from – M + 2 * F = 30
-50 + 2 * F = 30
2 * F = 30 + 50
F = 40.
If 15 females are absent, then number of males will be twice
that of females.
40 – 15 = 25.
50 = 2 * 25. Confirmed.
If also 45 males were absent, then female strength would be
5 times that of males.
Female strength is 25 due to the 15 females being absent.
50 – 45 = 5.
25 = 5 * 5. Confirmed.
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Ques:- A school has 30% students from Maharashtra .Out of these 20% are Bombey students. Find the total percentage of Bombay?
Recent Answer : Added by Alimam Ali On 2022-04-02 06:59:13:
66.66%
Ques:- The price of an article is cut by 20%. To restore it to the Former value, the new price must be increased by
A. 20%
B. 24%
C. 25%
D. 28%
Recent Answer : Added by Aayush Lodha On 2022-03-09 16:31:45:
LET ACTUAL PRICE BE 100 RS(FOR CONVINIENCE)
THEREFORE IF PRICE IS CUT BY 20%
THEREFORE NEW PRICE=100-20=80 RS
THEREFORE WE NEED TO ADD X% TO 80 RS TO MAKE IT 20 RS AND ADD IT TO 80 TO MAKE IT 100RS
THEREFORE, 80X/100 = 20
I.E. 4X/5=20
THEREFORE x=20*5/4
=5*5
=25
HENCE 25% OF PRICE SHOULD BE ADDED TO MAKE THE PRICE EQUAL TO THE ACTUAL PRICE.
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A
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264
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0
Ques:- Find the odd man out:
10, 25, 45, 54, 60, 75, 80
A. 75
B. 54
C. 45
D. 10
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54
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Recent Answer : Added by Kingsley On 2022-08-14 16:31:29:
Y
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63:45:55
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Ques:- area of triangle=1/2*b*h base incresed by 4 times & height is devided by 2, the net effect of area
Recent Answer : Added by Admin On 2020-05-17 11:59:59:
X = 1/2 * b*h
base incresed by 4 times & height
is devided by 2
X = 1/2 * 4b * h/2
X = h/4 * 4b
X = hb
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five multiplication & three addtion
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Ques:- If the wheel is 14 cm then the number of revolutions to cover a distance of 1056 cm is?
Recent Answer : Added by Subham Hazra On 2022-08-24 17:03:46:
Total number of pairs is NC2^{N}C_2NC2. Number of pairs standing next to each other = N. Therefore, number of pairs in question = NC2^{N}C_2NC2 – N = 28/2 = 14. If N = 7,
7C2 – 7 = 21 – 7 = 14….
N =7