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Ques:- Five years ago, the total of the ages of a father and his son was 40 years. The ratio of their present ages is 4 : 1. What is the present age of the father?
A. 20 years
B. 30 years
C. 40 years
D. 50 years
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Recent Answer :
: A
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Recent Answer :
: 8925
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Ques:- Four Members A,B,C,D are playing a game .A person losing a game should double the amount of others .B,C,D are losing in order after three games .The amount after 3 games are A&B having 40,D is having 16&C 80. Each questions carry one mark:
a) who started with small amount of money?
b) who started with greatest amount of money?
c) what amount did B have?
a) who started with small amount of money?
b) who started with greatest amount of money?
c) what amount did B have?
Recent Answer :
: status after 3 games
A-40
B-40
c-80
d-16
status after 2 games
A-20
B-20
C-40
D-96
status after 1 game
A-10
B-10
C-108
D-48
status after 0 games
A-5
B-93
C-54
D-24
so answers are
a)A
b)B
c)93
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Recent Answer :
: 3.14
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Recent Answer :
: i will put my sincere effort in my work for upward growth
of my career as well as my company.
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Recent Answer :
: let d distance and s be speed.
d/7 = x and d/5 = x+12
solving we get d=210.
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Let x be fathers present age and y be son present age.
5 yrs ago, the age of father and son be x-5 & y-5.
Then,
x-5+y-5=40
x+y-10=40
x+y=50
y=50-x ———–> (1)
ratio between father and son in present age
x:y=4:1
x/y=4/1
x=4y
Apply eq (1) ,
x=4(50-x)
x=200-4x
x+4x=200
5x=200
x=200/5
x=40,,
=> The present age of father is 40.