es, of course, there are a lot of people who start their careers with small things but after a few years, they grow themselves and get into better places. All you have to do is learn the skills of your desired domain while working on the other part and then use that to get a job in your desired place.
For example, consider you are an engineer and worked in a firm where you worked as a sales executive but you want to work as an IT professional in any IT firm then while working as a sales executive you can try to learn some coding languages like C or Java and after getting a good command on that you can apply for a job of developer or any IT professional. The only disadvantage is that your sales experience will have nothing to contribute to your IT job so you’ll be hired and paid as a fresher only.
I hope this helps you.
1/24-1/40
(5-3)/120
2/120
1/60
60 minutes
I need a answers from hakuna matata questions
To determine how many consecutive zeros the product of S will end with, we need to find the highest power of 10 that divides the product. This is equivalent to finding the highest power of 5 that divides the product, since the number of factors of 2 will always be greater than the number of factors of 5.
The primes in S are {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97}.
There are 24 primes in S, so the product of S is:
2 x 3 x 5 x 7 x 11 x 13 x 17 x 19 x 23 x 29 x 31 x 37 x 41 x 43 x 47 x 53 x 59 x 61 x 67 x 71 x 73 x 79 x 83 x 89 x 97
We need to find the highest power of 5 that divides this product. To do this, we count the number of factors of 5 in the prime factorization of each number in S.
5 appears once: 5
5 appears once: 25
5 appears once: 35
5 appears once: 55
5 appears once: 65
5 appears once: 85
So, there are six factors of 5 in the product of S. However, we also need to consider the powers of 5 that arise from the factors 25, 35, 55, and 65.
25 = 5 x 5 appears once: 25
35 = 5 x 7 appears once: 35
55 = 5 x 11 appears once: 55
65 = 5 x 13 appears once: 65
Each of these numbers contributes an additional factor of 5 to the product of S. Therefore, there are 6 + 4 = 10 factors of 5 in the product of S.
Since each factor of 5 corresponds to a factor of 10, we know that the product of S will end with 10 zeros. Therefore, the product of S will end with 10 consecutive zeros
3
6
1.5 hrs
6.35
Total 60 trees
4 rows each with 15 trees
5 rows each with 12 trees
6 rows each with 10 trees
to reach land
first time it travels 8 mtrs
next time (half=4) 4+4 mtrs (up&down)
next time (half=4) 2+2 mtrs (up&down)
next time (half=4) 1+1 mtrs (up&down)
and so on.
Altogether,close to 24 mtrs.
610 × 717 × 1127
= (2 × 3)10 × 717 × 1127
= 210 × 310 × 717 × 1127
Number of prime factors in the given expression
= (10 + 10 + 17 + 27)
= 64
accountant trainee at thenational board of accountants and auditors