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Ques:- There is a 5digit no. 3 pairs of sum is eleven each. Last digit is 3 times the first one. 3 rd digit is 3 less than the second. 4 th digit is 4 more than the second one. Find the digit.
Recent Answer : Added by Admin On 2020-05-17 11:59:40:
let first digit be ‘X’
then 5th digit is ‘3X’
let 2nd digit be ‘Y’
then 3rd digit is ‘Y-3’
and 4th digit is ‘Y+4’
then the no is ‘(X)(Y)(Y-3)(Y+4)(3X)’
from the above we can say 3X<=9
so X<=3 and any of the digit in the number is <=9
and also given that 3 pairs sum is 11...
so make trial and error..
if X=1...any of the no is 10 which is wrong trial....
if X=2...then let Y+4=9 ==> Y=5
then no is 25296
first pair 2+9=11
second pair 2+9=11
third pair 5+6=11
now the answer is 25296
Ques:- Find the smallest four-digit number which is a multiple of 112?
Recent Answer : Added by Admin On 2022-09-29 19:09:33:
Calculation:
⇒ If 1000 divided by 112, the remainder is 104. ⇒ 112 – 104 = 8 ⇒ If 8 is added to 1000 it will become the smallest four-digit number and a multiple of 112. ⇒ 1000 + 8 = 1008 ∴ The required result will be 1008.
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Chi-ca-go
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Recent Answer : Added by Admin On 2020-05-17 11:59:45:
ans: none
let it may be any number the square cant end in 8
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Ques:- Mr. Rahul spends 30% of his monthly salary on domestic expenses. He spends respectively 20% and 10% of the remaining salary on education of children and conveyance. Of the remaining amounts now he spends respectively 20% and 30%on entertainment and maintenance of house. He saves Rs.5512.50. what is the monthly salary of Mr. Rahul?
A. Rs. 22,500
B. Rs. 20,000
C. Rs. 25,000
D. Rs. 24,500
E. None of these
Recent Answer : Added by Admin On 2020-05-17 12:03:47:
How it is possible ? Please write in detail !!! This answer
s not a use !!!
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Recent Answer : Added by Durai On 2023-05-11 12:54:20:
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let first digit be ‘X’
then 5th digit is ‘3X’
let 2nd digit be ‘Y’
then 3rd digit is ‘Y-3’
and 4th digit is ‘Y+4’
then the no is ‘(X)(Y)(Y-3)(Y+4)(3X)’
from the above we can say 3X<=9 so X<=3 and any of the digit in the number is <=9 and also given that 3 pairs sum is 11... so make trial and error.. if X=1...any of the no is 10 which is wrong trial.... if X=2...then let Y+4=9 ==> Y=5
then no is 25296
first pair 2+9=11
second pair 2+9=11
third pair 5+6=11
now the answer is 25296