360 years old
Nepo’s son age = x
Nepo’s age = 3x
Nepo’s father age = 2*3x + 40
x + 3x + 6x + 40 = 1240
10x = 1200
x = 120
Nepos age = 3* 120 = 360 years
Let the number of one rupee coins in the bag be x.
Number of 50 paise coins in the bag is 93 – x.
Total value of coins
[100x + 50(93 – x)]paise = 5600 paise
=> x = 74
ANS = 74
Take 5 pills from jar 1, 4 pills from jar2,…. and 1 pill
from jar 5 and put altogether in the scale. the ideal
weight should be (1+2+3+4+5)x10= 150gms. for eg if the jar2
is contaminated then the weight will be 146 gms. so
depending on the amount of weight loss we can identify the
contaminated jar.
RABBIT
23.5 days
9 days
2*3(15+4)=114
114*1/2=57 rs
40
simple logic, Check Option Lets father present age = 40 so it full fill all condition like his son age become 10 and after five years it will become 15 and father age is 45 and it full fill second condition that fathers age is thrice as old as the son after 5 years
Let Suvarna, Tara, Uma and Vibha be S,T,U,V respectively
initially in the beginning each persons share be
V = x U = y T = z
S = w = (x+y+z+32) Reason: She has to double others share, so she should have each and everyone’s share and still should be left out with 32
after 1st Round of game
S loses and is out with 32 and doubles the others share
V = 2x U = 2y T = 2z
After 2nd Round of game
T loses and is out with 32 and doubles the others share
V = 4x U = 4y
This means T had 2z = 2x + 2y + 32
After 3rd round of game
U looses and is out with 32 and doubles others share
V = 8x
This means U initially has 4y = 4x + 32
In the end V = 8x = 32
Solving this we get x = 4, y = 12, z = 32 and w = 80
There fore Suvarna had highest share in the beginning
24 times
Ans is 2(Prime numbers)
Sum of 5 consecutive nos is 35
so X + (X+1) + (X+2) + (X+3)+ (X+4) = 35
5X + 10 = 35
X = 5
So the 5 consecutive numbers are : 5, 6, 7, 8, 9
The Prime numbers are 5 and 7
9
T is the last speaker.
5x/4
d=5
g=1
a=4, b=6,c=2,d=5,e=8,f=3,g=1,h=9,i=7