Ques:- A person walks 4 km towards west, then turns to his right to travel 9 km. He turns towards east and travels 12 km. Finally, he travels 3 km towards south. How far is he from the initial position (in km) ?
Recent Answer : Added by Pratyusha On 2021-09-02 08:08:04:
Answer is 10km
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Ques:- 2 men are walking towards each other at constant speeds.A train starting at one end crosses the first man in 18 seconds. After 10 minutes it meets the other man and crosses him in 12 seconds.(i am not sure of the values).Find the time when the 2 …
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Ques:- There are 6 red shoes & 4 green shoes . If two of red shoes are drawn what is the probability of getting red shoes
Recent Answer : Added by nilu On 2021-10-08 16:31:44:
5/9
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Ques:- A man collects cigarette stubs and makes one full cigarette with every 8 stubs. If he gets 64 stubs how many full cigarettes can he smoke
Recent Answer : Added by Nikhil Dandge On 2021-09-07 16:10:18:
9 because from 64 stubs 8 cigarettes and again from 8 stubs he’ll get 1 cigarette then his score will be 9
Ques:- In a bag there are coins of 50 paisa, 25 paisa and one rupee in the proportion 5:6:2. If there are in all Rs.42, the number of 25 paisa coins is?
Recent Answer : Added by kunal kumar singh On 2022-09-02 17:03:01:
42
Ques:- If in a certain language, NATURE is coded as MASUQE, how is FAMINE coded in that code ?
Recent Answer : Added by Nagarjuna On 2022-10-27 17:33:14:
EALIME
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Ques:- 1. A plane travels 695km with wind and 498km aginst the wind in same time.The speed of wind is 21km/hr. Find the speed of plane?
Recent Answer : Added by Admin On 2020-05-17 12:01:01:
127.179(app)
given distance of the train along the wind is 695
and againt the wind is 498
and time = distance/speed
as we know that time is equal in both the cases hence equate
695/s1=498/s2———–(1);
where s1=speed of the plane + speed of the wind
and s2=speed of the plane -speed of the wind
given that speed of the wind is 21k/h
s1=sp+21
s2=sp-21
substitu in eq 1
we get the answer as 27.17(app)
Ques:- Find the four digit number in which the first digit is 1/3 of the second, the third is the sum of the first and second, and the last is three times the second.
Recent Answer : Added by Pankhudi Agarwal On 2020-10-02 05:47:29:
let the 4 digit number be ABCD.
First Digit is A :
Therefore; according to the question
A=B/3
B=3A
C=A+B=A+3A=4A
D=3B=3(3A)=9A
Since the last Digit is D and it can neither be double-digit nor 0 ;
Therefore ;
A=1;
B=3A=3(1)=3
C=A+B=1+3=4
D=9A=9(1)=9
Therefore, the 4 digit number is 1349.
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Ques:- Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours. C is closed A and B can fill the remaining par in 7 hours. The number of hours taken by C alone to fill the tank is?
Recent Answer : Added by Mohit Hurkat On 2022-01-08 16:07:14:
13.5
Ques:- A train covered x km at 40 kmph and another 2x km at 20 kmph. Find the average speed of the train in covering the entire 3x km.
Recent Answer : Added by Rakesh Keshri On 2021-09-07 17:39:41:
24kmph
time taken = x/40 + 2x/20
=> x=8
so, 3x = 24
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Ques:- A 600 meter long train crosses a signal post in 40 seconds. How long will it take to cross a 3 kilometer long bridge, at the same speed?
Recent Answer : Added by vinita On 2022-08-14 16:33:16:
4 mins
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Ques:- A person invested in all Rs. 2600 at 4%, 6% and 8% per annum simple interest. At the end of the year, he got the same interest in all the three cases. The money invested at 4% is?
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Ques:- A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
Recent Answer : Added by Ben Gulliano On 2023-05-23 15:53:20:
– While the train is moving, the jogger will also be running in the same direction.
– for the head(engine) of the train to get to the current position of the jogger 240m away, it will take:
45km/hr => 12.5m/s => 240/12.5 = 19.2 seconds.
– But in the same period of time, the jogger will still be running and will have moved to a new location by: 9km/hr => 2.5m/s => 2.5 * 19.2 = 48m
To get to the new location at the speed of 12.5m/s will take the train:
48/12.5 = 3.84sec
In this additional time, the jogger will move forward by:
3.84 * 2.5 = 9.6m
at a speed of 12.5m/s, it will take the train less than a second to cover the additional 9.6m
If we add the distance the jogger will cover in 1 second to 9.6, it is still less than what the train can cover per second. let us see (9.6 + 2.5 = 12.1)
Therefore, the head of the train will pass the runner at approximately: 19.2 + 3.84 + 1 => 24.04 seconds.
For the train to completely pass the runner, it will need its whole length of 120m to be in front of the runner.
This will take an additional (9.6 + 2) seconds.
Therefore for the length of the train to be ahead of the runner it will take approx. 35.65 (24.04 + 9.6 + 2) seconds
Answer is 10km