Red lobster Interview Questions, Process, and Tips

1600 years contain 0 odd day.
300 years contain 1 odd day.
94 years = (23 leap years + 71 ordinary years)
= (46 + 71) odd days
= 117 odd days, i.e., 5 odd days
Days from 1st January 1995 to 28th February 1995
= (31 + 28) days = 59 days
= (8 weeks + 3 days) = 3 odd days
∴ Total number of odd days
= (0 + 1 + 5 + 3) = 9 odd days i.e., 2 odd days.
So, the required day is Tuesday.

835,sum(digits)= 16
734 = 14
642=12
751= 13,
853=16,
981=18,
532=10

answer(c)751

24000

The most important belief is belief in yourself. Believing in who you are and your abilities frees you to pursue goals and dreams without reservation and drives you forward with confidence, independence, autonomy and direction. Combine this conviction in yourself with a solid framework of inherent beliefs from the list above, and you have an unbeatable combination.

Divide 30*60 seconds by LCM of Numbers =15

let present age of ANAND AND BALA BE( A AND B ) RESPECTIVELY

A.T.Q

(A-10) = 1/3[B-10]. ……… – {1}

given

B = A+ 12 PUTTING IN 1

THEREFORE A-10 = 1/3 (A+2) = A+2 = 3A – 30

2A =32

A=16

5 is the answer….
Remaining all are the multiples of 3 expect 5

5x/4

The answer for this question is very simple: it is called Ceaser Cipher.
It consists of replacing a character by another located in (current character position + (key-1)), where key = how many positions you want to skip.
For Example: VICTORY -> YLFWRUB with the key = 3.
Then SUCCESS -> QXFFHQQ

Note: it should work like a circle(Z+1 = A).

2400

(T-P)-(U-Q)-(V-R)-(W-S)
S Opposite is Q
U sits the P and Q