Ques:- The price of an article is cut by 20%. To restore it to the Former value, the new price must be increased by
A. 20%
B. 24%
C. 25%
D. 28%
Recent Answer : Added by Aayush Lodha On 2022-03-09 16:31:45:
LET ACTUAL PRICE BE 100 RS(FOR CONVINIENCE)
THEREFORE IF PRICE IS CUT BY 20%
THEREFORE NEW PRICE=100-20=80 RS
THEREFORE WE NEED TO ADD X% TO 80 RS TO MAKE IT 20 RS AND ADD IT TO 80 TO MAKE IT 100RS
THEREFORE, 80X/100 = 20
I.E. 4X/5=20
THEREFORE x=20*5/4
=5*5
=25
HENCE 25% OF PRICE SHOULD BE ADDED TO MAKE THE PRICE EQUAL TO THE ACTUAL PRICE.
Ques:- What are the differences between Pascal and C.
Recent Answer : Added by Admin On 2020-05-17 12:02:26:
c-> structured oriented lang
Pascal-> Procedure oriented lang
Ques:- When x is real what is the least value of (x**2-6*x+5)/(x**2+2*x+1)
Recent Answer : Added by Admin On 2020-05-17 12:01:23:
(x**2 – 6* x + 5) = (x-1)*(x-5)
(x**2 + 2 * x + 1) = (x + 1) * (x+1) = (x+1)**2
For what x is (x-1)*(x-5)/( (x+1)**2) a minimum?
One way to answer this question is by using calculus.
Take the derivative, and set to zero.
Since this is a fraction of polynomials, and a fraction is
zero only if it’s numerator is zero, we need calculate only
the numerator of the derivative and set it to zero.
The numerator of the
Derivative of (x-1)*(x-5)/( (x+1)**2) is
( (x-1) + (x-5) ) ( x+1)**2 – (x-1)(x-5)( 2 (x+1) )
= (2 x – 6) (x+1)**2 – (2) (x-1)(x-5) (x+1)
= 0
Divide through by 2 (x+1)
(x-3)(x+1) – (x-1)(x-5) = 0
(x**2 – 2 x – 3 ) – (x**2 – 6 x + 5) = 0
x**2 – x**2 – 2 x + 6 x – 3 – 5 = 0
4 x – 8 = 0
x = 2
Plugging in x = 2 into the original
(x**2-6*x+5)/(x**2+2*x+1)
gives us (2**2 – 6 * 2 + 5)/(2**2 + 2*2 + 1)
= (4 – 12 + 5) / (4 + 4 + 1) = -3/9 = -1/3
Least value is -1/3
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Recent Answer : Added by DK BOSS On 2021-07-15 05:30:04:
acno is right answer
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FLRIHO=cooler
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Recent Answer : Added by Mahomed On 2021-08-24 15:05:46:
All books can be arranged in 10! ways. A single pair of books can be taken as a unit and arranged among the 8 others in 9! ways. The pair of books can also be interchanged and therefore rearranged in 2! ways. Thus the probability of the pair always being together is (9!*2!)/10!
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11
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Ques:- A car is journied a certain distance in 7 hrs in forward journey in the return journey increased speed 12km/hr takes the times 5 hrs. what is the distance
Recent Answer : Added by Admin On 2020-05-17 11:59:58:
let d distance and s be speed.
d/7 = x and d/5 = x+12
solving we get d=210.
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Ques:- The H.C.F. of 0.54, 1.8 and 7.2 is
A. 0.18
B. 0.018
C. 1.8
D. 18
Recent Answer : Added by vishakha yadav On 2022-05-17 08:54:24:
0.18
Ques:- While packing some return gifts, a mother decides to put some toffees in each gift packet. If she keeps 5 toffees in each packet, she is left with none. But if she keeps 2, 3 or 4 toffees in a packet, she is left with 1 toffee . What is the minimum number of toffees that she needs?
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Ques:- Murali travelled from city A to city B at a speed of 40 kmph and from city B to city C at 60 kmph. What is the average speed of Murali from A to C given that the ratio of distances between A to B and B to C is 2 : 3?
Recent Answer : Added by DK BOSS On 2021-07-17 06:18:20:
Answer: 50 kmph.
Explanation:
Let the distances between city A to B and B to C be 2x km and 3x km respectively.
Total time taken to cover from A to C
= (2x)/40 + (3x)/60 = (6x + 6x)/120 = 12x/120 = x/10 Average speed = (2x + 3x)/(x/10) = 50 kmph.
LET ACTUAL PRICE BE 100 RS(FOR CONVINIENCE)
THEREFORE IF PRICE IS CUT BY 20%
THEREFORE NEW PRICE=100-20=80 RS
THEREFORE WE NEED TO ADD X% TO 80 RS TO MAKE IT 20 RS AND ADD IT TO 80 TO MAKE IT 100RS
THEREFORE, 80X/100 = 20
I.E. 4X/5=20
THEREFORE x=20*5/4
=5*5
=25
HENCE 25% OF PRICE SHOULD BE ADDED TO MAKE THE PRICE EQUAL TO THE ACTUAL PRICE.