Ques:- Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is?
Recent Answer : Added by Admin On 2022-09-29 17:57:30:
Relative speed = 60 + 90 = 150 km/hr.
= 150 x 5/18 = 125/3 m/sec.
Distance covered = 1.10 + 0.9 = 2 km = 2000 m.
Required time = 2000 x 3/125 = 48 sec.
Ques:- A man swims downstream 72 km and upstream 45 km taking 9 hours each time; what is the speed of the current?
Recent Answer : Added by Admin On 2022-09-29 16:19:13:
Explanation:
72 — 9
? —- 1
=> Down Stream = 8
45 —- 9
? —- 1
=> Up Stream = 5
Speed od current S = ?
S = (8 – 5)/2 = 1.5 kmph.
Ques:- A train 240 m in length crosses a telegraph post in 16 seconds. What is the speed of the train ?
Recent Answer : Added by jay On 2022-03-09 16:41:09:
speed = distance / time.
240/16=15m/sec=54km/hr
Ques:- Why do you expect this much salary?
Ques:- What is your major accommplishment?
Ques:- Why are manhole covers round?
Recent Answer : Added by Tinashe D Ganyara On 2022-03-09 16:37:50:
So as to prevent unauthorized persons from entering and reducing vandalism
Ques:- Would you be able to manage travelling as you are presently in sitting jobs & will you be able to handel a team of set people?
Ques:- Do you have any past heroes?
Ques:- If every alternative letter starting from B of the English alphabet is written in small letter, rest all are written in capital letters, how the month “September” be written. (1) SeptEMbEr (2) SEpTeMBEr (3) SeptembeR (4) SepteMber (5) None of the above.
Ques:- “A contribution of Rs. 500 was raised from 500 people. The fee was as follows:Men: Rs.3.00 each Women: Rs. 2.00 each Childern: 0.48 each If number of women is more than number of men, how many childern are there?”
Ques:- A reduction of 20% in the price of salt enables a lady to obtain 10kgs more for Rs.100, find the original price per kg?
Ques:- A fort of 2000 soldiers has provisions for 50 days. After 10 days some of them left and the food was now enough for the same period of 50 days as before. How many of them left?
Recent Answer : Added by Agboola Al-Mubarak Dosunmu On 2020-12-09 15:07:45:
400
Ques:- AT WHAT YOU ARE THE BEST ?
Ques:- Two buses start from the opposite points of a main road, 150 kms apart. The first bus runs for 25 kms and takes a right turn and then runs for 15 kms. It then turns left and runs for another 25 kms and takes the direction back to reach the main road. In the meantime, due to a minor breakdown, the other bus run only 35 kms along the main road. What would be the distance between the buses at this point?
Recent Answer : Added by Pardip Divekar On 2021-06-23 17:55:33:
65 KM
Ques:- Why we hire you, being a fresher when at the same time wehave experinced professionals like CAs, MBAs line up?
Ques:- P?s father is Q’s son. M is the paternal uncle of P and N is the brother of Q. How is N related to M ?
A. Brother
B. Nephew
C. Cousin
D. Data inadequate
E. None of these
Ques:- Describe one of your memorable day?how is education useful for any body?
Ques:- Why am I interested in joining this company?
Ques:- What is the disappointment in your life?
Ques:- A man could buy a certain number of notebooks for Rs.300. If each notebook cost is Rs.5 more, he could have bought 10 notebooks less for the same amount. Find the price of each notebook?
Recent Answer : Added by Admin On 2022-09-29 19:24:04:
According to the question:
⇒(x+5)(y−10)=300
⇒xy+5y−10x−50=xy
⇒5×300−10x−50=0
⇒−150+x2+5x=0
⇒x2+15x−10x−150=0
⇒x(x+15)−10(x+15)=0
⇒x=10 or −15
Price cannot be negative
So, As x>0,x=10.
Ques:- Why I hire you and why i don't hire you?
Ques:- Are you familiar with collaboration tools? Whichcommunication method do you prefer for talk, email and chat?
Ques:- For 15 people–each has to pay Rs.20.For 20 people–each has to pay Rs.18. For 40 people–how much has each to pay ?
Recent Answer : Added by Admin On 2020-05-17 12:02:02:
FOR 15 = RS.20
FOR 20 = RS.18
FOR 25 = RS.16
FOR 30 = RS.14
FOR 35 = RS.12
FOR 40 = RS.10
Ques:- Two cars cover the same distance at the speed of 60 and 64 kmps respectively. Find the distance traveled by them if the slower car takes 1 hour more than the faster car.
Ques:- What is your greatest fear?
Ques:- Why you join the hotel industry?
Ques:- The present average age of a family of five members is 26 years. If the present age of the youngest member in the family is ten years, then what was the average age of the family at the time of the birth of the youngest member ? (Assume no death occurred in the family since the birth of the youngest)
Ques:- What would you like to do five years from now?
Ques:- Tell me about an important issue you encountered recently?
Ques:- 1) In a club there are certain no. of males and females. If 15 females are absent then no. of males will be twice that of females. If 45 males are absent then female strength will be 5 times that of males. Find no. of males actually present.
Recent Answer : Added by Admin On 2020-05-17 12:01:55:
Let the number of males be given the name M.
Let the number of females be given the name F.
If 15 females are absent, then M will be twice that of
present females.
This means that M = 2 * (F – 15)
M = 2 * F – 30.
or 2 * F – M = 30.
Now if in addition to the 15 females being absent, we also
have 45 males being absent,
then this gives the equation,
(F – 15) = 5 * (M – 45)
which simplifies to
F – 15 = 5 * M – 225
5 * M – F = 210
Pulling the equations together, we get
5 * M – F = 210
-M + 2 * F = 30
Multiply the first equation by 2, and keep the second
equation as is.
10 * M – 2 * F = 420
– M + 2 * F = 30
Add the equations.
9 * M = 450
M = 50
Verify answer.
Calculate F
from – M + 2 * F = 30
-50 + 2 * F = 30
2 * F = 30 + 50
F = 40.
If 15 females are absent, then number of males will be twice
that of females.
40 – 15 = 25.
50 = 2 * 25. Confirmed.
If also 45 males were absent, then female strength would be
5 times that of males.
Female strength is 25 due to the 15 females being absent.
50 – 45 = 5.
25 = 5 * 5. Confirmed.
Relative speed = 60 + 90 = 150 km/hr.
= 150 x 5/18 = 125/3 m/sec.
Distance covered = 1.10 + 0.9 = 2 km = 2000 m.
Required time = 2000 x 3/125 = 48 sec.