Verve talent & literary agency Interview Questions, Process, and Tips

Ques:- Number Series 11,14,12,15,13,16,?
Recent Answer : Added by Admin On 2020-05-17 11:59:56:

11 14
12 15
13 16
=======
14 17
the answers is 14

Ques:- Find out the wrong number in each sequence:
5, 16, 6, 16, 7, 16, 9
A. 6
B. 7
C. 8
D. 9
Recent Answer : Added by narendra On 2022-09-18 09:01:30:

d

Ques:- What is the optimal size of a project team, above which additional members do not contribute productivity equivalent to the percentage increase in the staff size?
Recent Answer : Added by Admin On 2020-05-17 12:01:51:

For optimal size of a project team..
the % increase in staff size should be “Zero”
reason:
additional member directly proportional to increase in
staff size..

Ques:- If x + 8y = 20 and x = -3y, then y =
Recent Answer : Added by David Evans Gyamfi On 2021-09-26 15:12:42:

x+8y=20, x=-3y
(-3y)+8y=20
5y=20
y=4
The answer for y is 4

Ques:- The largest natural number by which the product of three consecutive even natural numbers is always divisible by
A. 16
B. 24
C. 48
D. 96
Recent Answer : Added by Shashank Panddey On 2022-09-15 16:36:27:

Let three consecutive even numbers be 2n,2n+2,2n+4
product=2n(2n+2)(2n+4)
If n=1,
product =2(4)(6)=48.
So, all the numbers will be divisible by 48 if change n.

Ques:- A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
Recent Answer : Added by Ben Gulliano On 2023-05-23 15:53:20:

– While the train is moving, the jogger will also be running in the same direction.
– for the head(engine) of the train to get to the current position of the jogger 240m away, it will take:
45km/hr => 12.5m/s => 240/12.5 = 19.2 seconds.

– But in the same period of time, the jogger will still be running and will have moved to a new location by: 9km/hr => 2.5m/s => 2.5 * 19.2 = 48m

To get to the new location at the speed of 12.5m/s will take the train:
48/12.5 = 3.84sec

In this additional time, the jogger will move forward by:
3.84 * 2.5 = 9.6m

at a speed of 12.5m/s, it will take the train less than a second to cover the additional 9.6m

If we add the distance the jogger will cover in 1 second to 9.6, it is still less than what the train can cover per second. let us see (9.6 + 2.5 = 12.1)

Therefore, the head of the train will pass the runner at approximately: 19.2 + 3.84 + 1 => 24.04 seconds.

For the train to completely pass the runner, it will need its whole length of 120m to be in front of the runner.

This will take an additional (9.6 + 2) seconds.

Therefore for the length of the train to be ahead of the runner it will take approx. 35.65 (24.04 + 9.6 + 2) seconds

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