pass English =80%
fail=100-80=20%
pass Math = 70%
fail in Math=100-70=30%
fail in both=10%
total fail students= fail in Eng+fail in Math-common
= 20+30-10=40%
if 40% fail then 60% will pass
let total students=x
hence
60% 0f (total students)=144
60/100 of (x)= 144
x=(144×100)/60
X=240
total students=240
E: 80%, Fail in both: 10%, therefore only M pass is 10%
M: 70%, fail in both: 10%, therefore only E pass is 20%
100% = all fail + only E pass + only M pass + both E and M
pass
100%=10%+20%+10% + both E and M pass
Therefore, both E and M pass = 60%
60%=> 144
100% => 240
Answer: 240
pass English =80%
fail=100-80=20%
pass Math = 70%
fail in Math=100-70=30%
fail in both=10%
total fail students= fail in Eng+fail in Math-common
= 20+30-10=40%
if 40% fail then 60% will pass
let total students=x
hence
60% 0f (total students)=144
60/100 of (x)= 144
x=(144×100)/60
X=240
total students=240
E: 80%, Fail in both: 10%, therefore only M pass is 10%
M: 70%, fail in both: 10%, therefore only E pass is 20%
100% = all fail + only E pass + only M pass + both E and M
pass
100%=10%+20%+10% + both E and M pass
Therefore, both E and M pass = 60%
60%=> 144
100% => 240
Answer: 240