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the 4 digit numbers that will be formed from ( 6,2,7,5)with
no repetition, can not divisible by 36.
because these no. must be divisible by 6.
A no. will be divisible by 6 when it is also divisible by 2
and 3.
so some of these formed no. divisible by 2 ( eg.7562,5726
etc) but not divisible by 3
becase ( 7+5+6+2)=20 { according to divisibility check}
which is not multiple of 3.
no combinations is there because a number divisible by 36
also divisible by its divisors anu.sum of 4 digits=20,whis
is not multiple of 3.so it is cannot divisible by 3