A and B combinely can do a work in 4 days. If A alone can do a piece of work 6 days. In how many days B alone can do?

2 Answers on this Question

1. say the work is w and let no of days taken by b is ‘x’ which
   we have to calculate
   so work done by a in one day is w/6
   work done by b in one day is w/x
   a and b together can do work in 4 days ie=(w/6)+(w/x)=(w/4)
   solving equation x=12
   so no of days taken by b=12

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2. 12 days

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