A die is thrown twice n(s)=36 The probability of getting same number is (1,1)(2,2)(3,3) (4,4)(5,5)(6,6) i.e n(A)=6 Ans. P(A)=n(A)/n(s) = 6/36 =1/6. So, The Answer is 1/6 Reply
A die is thrown twice n(s)=36
The probability of getting same number is (1,1)(2,2)(3,3)
(4,4)(5,5)(6,6) i.e n(A)=6
Ans. P(A)=n(A)/n(s)
= 6/36
=1/6.
So, The Answer is 1/6