A man while going dowm in a escalator(which is miving down) takes 50 steps to reach down and while going up takes 125 steps. If he goes 5 times faster upwards than downwards. What will be the total no of steps if the escalator werent moving.

2 Answers on this Question

1. let A goes up and B comes down.
   assume A takes 1 step in 1sec.
   hence,B takes 5 steps in 1sec.
   50 steps ll be moved by A in 50/1=50secs
   125 steps ll be moved by B in 125/5=25 secs
   hence speed of escalator=(difference of no of
   steps)/(difference of time)
   speed=(125-50)/(50-25)= 3 steps/sec
   hence during upward journey of 50secs by A,total steps=50 by
   A and 150 by escalator..total=150+50=200
   during downward journey of 25 secs by B,total steps=125 by B
   and 75 by escalator..total=125+75=200steps.
   ANS:200 steps

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2. All the above answers are wrong.
   1. While going down he takes 50 steps and escalator moves x
   steps down
   50+x ….(1)
   2. 5 times faster while going up, 50*5=250 and still the
   escalator moves x steps down. so 250-x (2)
   Equating both the equns
   50+x = 250-x
   x=100
   use the x in any of the equation, that is the total number
   of steps in the escalator.
   When the person goes down 50 steps, escalator goes 100 steps
   down. So total number of steps in that escalator is 150.
   Period.

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