A starts from a place at 11.00 am and travels at a speed of 4 kmph , B starts at 1.00 pm and travels with speeds of 1 kmph for 1 hr , 2 kmph for the next hr , 3 kmph for the next hr and so on. At wht time will B catch up with A ?

A starts from a place at 11.00 am and travels at a speed of
4 kmph , B starts at 1.00 pm and travels with speeds of 1
kmph for 1 hr , 2 kmph for the next hr , 3 kmph for the
next hr and so on. At wht time will B catch up with A ?

Ques:- A starts from a place at 11.00 am and travels at a speed of 4 kmph , B starts at 1.00 pm and travels with speeds of 1 kmph for 1 hr , 2 kmph for the next hr , 3 kmph for the next hr and so on. At wht time will B catch up with A ?
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3 Answers on this Question

  1. At 1:00 pm the dif’n between A & B = 8 km
    after 2:00 pm ………………. = 11 km (as B’s speed
    is 1 and A’s 4km, then eqv speed=(4-1)=3km)
    After 3:00………………….. = 13km (as B’s speed 2km)
    After 4:00………………….. = 14km
    after 5:00………………….. = 14km (A’s speed= B’s
    speed)
    after 6:00………………….. = 13km
    after 7:00………………….. = 11km
    after 8:00………………….. = 8km
    after 9:00………………….. = 4km
    and now the eqv speed is= (9-4) =5km/hr;
    and the remaning distance is 4km;
    then, time=(60*4)/5=48 min;
    then the meeting time is=9:00+48min=9:48 pm;

  2. the answer is At 9:48 PM
    At 1:00 pm the difference between A & B = 8 km
    after 2:00 pm ………………. = 11 km (as B’s speed
    is 1 and A’s 4 km, then eqv speed=(4-1)=3 km)
    After 3:00………………….. = 13 km (as B’s speed 2 km)
    After 4:00………………….. = 14 km
    after 5:00………………….. = 14 km (A’s speed= B’s
    speed)
    after 6:00………………….. = 13 km
    after 7:00………………….. = 11 km
    after 8:00………………….. = 8 km
    after 9:00………………….. = 4 km
    and now the eqv speed is= (9-4) =5 km/hr;
    and the renaming distance is 4 km;
    then, time=(60*4)/5=48 min;
    then the meeting time is=9:00+48 min=9:48 pm;

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