To provide the best experiences, we use technologies like cookies to store and/or access device information. Consenting to these technologies will allow us to process data such as browsing behavior or unique IDs on this site. Not consenting or withdrawing consent, may adversely affect certain features and functions.
The technical storage or access is strictly necessary for the legitimate purpose of enabling the use of a specific service explicitly requested by the subscriber or user, or for the sole purpose of carrying out the transmission of a communication over an electronic communications network.
The technical storage or access is necessary for the legitimate purpose of storing preferences that are not requested by the subscriber or user.
The technical storage or access that is used exclusively for statistical purposes.
The technical storage or access that is used exclusively for anonymous statistical purposes. Without a subpoena, voluntary compliance on the part of your Internet Service Provider, or additional records from a third party, information stored or retrieved for this purpose alone cannot usually be used to identify you.
The technical storage or access is required to create user profiles to send advertising, or to track the user on a website or across several websites for similar marketing purposes.
30sec
30sec
Can anyone provide the solution ?
Total distance = ( 280 m + 220 m) = 500 m ; speed = 60 km/hr = 16.2 m/s ( convert km/hr to m/s {i.e multiple 60 by 5/18} )
speed = distance/ time
time = d/s = 500/16.2 = 30 s
Time = Distance/Speed
Total Distance = (280+220) = 500 m
Speed = 60 km/hr = 60*(5/18) m/s = 50/3 m/s
Time = 500/(50/3) = 1500/50 = 30 Sec.
Answer = 30 sec.
convert 60 km/hr into m/s.
we get (50/3)m/s.
now the total distance is 280m+220m = 500m
NOW APPLY THE FORMULA FOR GETTING THE TIME IS
S = D/T
T =D/S
T =( 500M) / (50/3) =30 seconds.
280m+220m=500m
280m for 60km/hrs.
60km/hr=16.7m/s.
Time taken for 500m to travel for 16.7m/s
500/16.7=30s
60 km/hr
60×5/18=50/3m/see
50/3 m cover 1 sec
So,500 m cover= (3/50)*500
=30 sec
Ans= 30 sec
Time = Distance/Speed
Total Distance = (280+220) = 500 m
Speed = 60 km/hr = 60*(5/18) m/s = 50/3 m/s
Time = 500/(50/3) = 1500/50 = 30 Sec.
Answer = 30 sec.
Correct option is D)
Distance=(280+220)m=500m
Speed=60 km/hr=>60×0.27=16.2
Then
By Speed Formula:speed =distance/time
Time=distance/speed
Then
Time=500/16.2=30s
Train 1st move dist. 280m at time is 60kmph.
Speed 1= d/t =280/60*5/18 = 17.2
Train to cross tunnel length. 220m at a time 60kmph.
Speed 2=d/t =220/60*5/18 = 13.5
Total time taken by the train =speed 1 + speed 2
=17.2+13.5 = ~30.7sec
I think,30sec is a answer.
Distance=(280+220)m=500m
Speed=60 km/hr=60× (5/18)m/sec=(50/3)m/sec
Time=500/(50/3)sec=30 sec
60 = 500×3600/tx1000
t = 30s
280+220/60*(5/18)=(500/60*5)*18=30
D = 280 + 220 = 500
S = 60 * 5/18 = 16.66
T = D/S = 500/16.66
T = 30S
30 Sec