A traveler walks a certain distance. Had he gone half a kilometer an hour faster , he would have walked it in 4/5 of the time, and had he gone half a Kilometer an hour slower, he would have walked 2 ½ hr longer. What is the distance?

3 Answers on this Question

1. let d be distance and x be speed and t be time.
   hence ,
   d / (x+1/2) = 4/5 * t
   and d / (x-1/2) = 5/2 + t
   solving we get d = 15.

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2. let distance=x , time=t & speed=s &v knw x=s*t …. (1)
   1st case x=(s+.5)(4t/5) ….. (2)
   2nd case x=(s-.5)(t+ 5/2) ….. (3)
   (1) divided by (2) v get speed s = 2
   similarly (2) divided by (3) v get time t = 15/2
   therefore x = s * t = 2 * 15/2 = 15 km

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3. d / (x+1/2) = 4/5 * t
   and d / (x-1/2) = 5/2 + t
   solving we get d = 15.

   Reply