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the question generally means – to identify the no of words
in which starting letter and the ending letter must have
the same position difference as in English alphabet
here STAINLESS has two such pairs
ST – in alphabetical order.
A(INL)E WHICH MEANS A(BCD)E – A and E have three alphabets
in between.
in some books i also found that the word is scanned from
right and not from left.
my answer would be (a) two
Dear friends i ofcourse confused like you when i come
across to solve this problem. Really friends its very
simple if you understand the question clearly. First thing
is what is mean by “as many as” means its called ‘idiom and
phrase’ in english and it means “the same number of”. now
read the question “how many pairs of letters in STAINLESS
which has same number of letters between them in the word
as they have in english alphabet”.
In the alphabetical order, A-Z can be numbered as 1-26.
In A(INL)E which is same as in the alphabetical order A
(BCD)E. In both the cases E is in the Fourth position. so
we got one pair.
And in ST, there are no letters between them in the word
stainless. In alphabetical orer from A-Z also there is no
letters between them..so we got the second pair…
In STAINLESS it has two pairs ST and AE