If a salesman’s average is a new order every other week, he will break the office record of the year. However, after 28 weeks, he is six orders behind schedule. In what proportion of the remaining weeks does he have to obtain a new order to break the record?

If a salesman’s average is a new order every other week, he will break the office record of the year.  However, after 28 weeks, he is six orders behind schedule.  In what proportion of the remaining weeks does he have to obtain a new order to break the record?

Ques:- If a salesman’s average is a new order every other week, he will break the office record of the year. However, after 28 weeks, he is six orders behind schedule. In what proportion of the remaining weeks does he have to obtain a new order to break the record?
4 1760

4 Answers on this Question

  1. no f weeks in a yr=52
    26 orders required for the creation f record..
    son after 28 weeks no f order should b 14..
    the person z short by 8 orders ..
    dat means in the nxt 24 weeks he need to cllct 18(26-8) orders
    so proportion f order to remaining weeks z 18/24= 3/4

  2. terrible answer,Kris,
    it is simply like that,
    6/(52-28) is the prop the sales to do
    that means it is to do 1-(1/4)=3/4 to get it ;

  3. 52 weeks a year.

    52-28= 24 weeks remaining
    24/2= 12 regular average
    12 + 6 = 18 above average to make up time lost
    18/24 = 3/4 sales per week (or 3 sales per 4 weeks)

  4. Assume there are 52 weeks in one year.
    Since he supposed to have a new order for every two weeks, he
    needs 52/2 = 26 orders to break the office record.

    Now after 28 weeks,he has got only 28/2 -6 = 8 orders.

    Hence,he needs 26-8 = 18 new orders in the remaining 24= 52-28 weeks to break the office record.

    Compute 24 orders/18 weeks = 4/3 orders/week ,
    we see that averagely he has a new order for
    every 4/3 weeks in the remaining weeks to break the office record.

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