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let the third no be x ,
then the first no is 3x ,
second no is 2*3x ie 6x
average is (3x+6x+x )/3 = 20
10x/3 = 20
x= 60/10 = 6
third no is 6 , second is 6x = 36, first no is 3x = 18
largest no is 36 i.e second no
let x,y,z be numbers in order
y=2x,x=3z
(x+y+z)/3=20
(x+2x+(x/3))/9=20
solving
x=18
y=36
z=6
so largest is y=36