If second no is twice the first no and first no is thrice the third no.Their avg is 20.Find the greatest no?

2 Answers on this Question

1. let the third no be x ,
   then the first no is 3x ,
   second no is 2*3x ie 6x
   average is (3x+6x+x )/3 = 20
   10x/3 = 20
   x= 60/10 = 6
   third no is 6 , second is 6x = 36, first no is 3x = 18
   largest no is 36 i.e second no

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2. let x,y,z be numbers in order
   y=2x,x=3z
   (x+y+z)/3=20
   (x+2x+(x/3))/9=20
   solving
   x=18
   y=36
   z=6
   so largest is y=36

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