In 3.5 Kg rod , there is 74% silver. If it is alloyed with a 0.5 Kg rod, the % of silver goes p to 84%. The percent of silver in 0.5 Kg rod?

3 Answers on this Question

1. In 3500gm rod 74% is silver = 2590gm
   500gm rod is added total weight becomes 4000gm
   In 4000gm 84% is silver =3360gm
   diff in silver =770gm
   So by adding 500gm of rod 770gm of silver is increased,
   which is not possible.

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2. The percentage of silver in 0.5 kg rod is 10.5%.

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3. In 3500 g rod contains 74% of silver = 3500 * 74/100 = 2590 g
   Then 3500 g + 500 g of rod contains 84% of silver
   Let x be the silver contained in 500 g of silver
   (2590/3500 * 100) + (x/500 * 100) = 84
   74 + x/5 = 84
   (370 + x) /5 = 84
   370 + x = 420
   x = 50
   Then the percentage of silver contained in 500 g of rod = 50/500 *100 =10%

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