Given: In a group of 15 students, 7 have studied Latin, 8 have studied Greek, 3 have not studied either. To find: The number of students who studied both Latin and Greek. Solution: In a group of 15 students, have studied Latin, 8 have studied Greek, 3 have not studied either. Therefore, n(A∪B) = 15 – 3 n(A∪B) = 12 7 have studied Latin, n(A) = 7 8 have studied Greek, n(B) = 8 n(A∩B) is the number of students who studied both Latin and Greek. n(A∩B) = n(A) + n(B) – n(A∪B) n(A∩B) = 7 + 8 – 12 n(A∩B) = 15 – 12 n(A∩B) = 3 The number of students who studied both Latin and Greek is 3 Final answer: 3 of them studied both Latin and Greek. Thus, the correct answer .3 Reply
Given:
In a group of 15 students,
7 have studied Latin,
8 have studied Greek,
3 have not studied either.
To find:
The number of students who studied both Latin and Greek.
Solution:
In a group of 15 students, have studied Latin, 8 have studied Greek, 3 have not studied either.
Therefore,
n(A∪B) = 15 – 3
n(A∪B) = 12
7 have studied Latin,
n(A) = 7
8 have studied Greek,
n(B) = 8
n(A∩B) is the number of students who studied both Latin and Greek.
n(A∩B) = n(A) + n(B) – n(A∪B)
n(A∩B) = 7 + 8 – 12
n(A∩B) = 15 – 12
n(A∩B) = 3
The number of students who studied both Latin and Greek is 3
Final answer:
3 of them studied both Latin and Greek.
Thus, the correct answer .3