1×2×…100=100! Number of zeros in product of n numbers =[5n]+[52n]+[53n]+… Number of zeros in product of 100 numbers =[5100]+[52100]+[53100] where [.] is greatest integer function =[20]+[4]+[0.8]=20+4=24 Reply
1×2×…100=100!
Number of zeros in product of n numbers =[5n]+[52n]+[53n]+…
Number of zeros in product of 100 numbers =[5100]+[52100]+[53100]
where [.] is greatest integer function
=[20]+[4]+[0.8]=20+4=24