The three boxes 1,2,3 has values resp. AB,BC,AC Get 2A(B+C) +AC-2C(A-B)in Box 1 using only addition in 3 steps.

2 Answers on this Question

1. GIVEN: 2A(B+C)+AC-2C(A-B)
   THEREFORE 2AB+2AC+AC-2AC+2BC
   2AB+AC+2BC
   2(AB+BC)+AC
   LET b1=AB b2=BC b3=AC
   STEP1: b1 = b1+b2
   so b1 = AB+BC
   THEREFORE
   NOW: b1 = AB+BC b2 = BC b3 = AC
   STEP 2: b3 = b1+b3
   so b3 = AB+BC+AC
   THEREFORE
   NOW: b1 = AB+BC b2 = BC b3 = AB+BC+AC
   STEP3:
   NOW: b1 = b1+b3
   so b1 = AB+BC+AB+BC+AC
   =2(AB+BC)+ AC
   AB BC AC
   STEP1 AB+BC BC AC
   STEP2 AC BC AB+BC+AC
   STEP3 AB+BC+AB+BC+AC BC AB+BC+AC
   i.e 2(AB+BC)+AC BC AB+BC+AC

   Reply

2. Same as above but step 2 should be add box 1 to box 1. A
   little pedantic but but I would deduct marks for not meeting
   the requirements.

   Reply