The question doesn’t entirely make sense. I’m going to
assume you meant this:
“There are 6 red shoes & 4 green shoes . If two shoes
are drawn at random what is the probability they are both red?”
The probability that the first shoe will be red is 6 (red
shoes) / 10 (total shoes) = 60%.
The probability that the second shoe will be red is 5
(remaining red shoes) / 9 (remaining shoes) = 55.6%.
60% * 55.6% = 33%. Therefore, the chance of drawing two red
shoes is 1/3.
6c2/10c2
The question doesn’t entirely make sense. I’m going to
assume you meant this:
“There are 6 red shoes & 4 green shoes . If two shoes
are drawn at random what is the probability they are both red?”
The probability that the first shoe will be red is 6 (red
shoes) / 10 (total shoes) = 60%.
The probability that the second shoe will be red is 5
(remaining red shoes) / 9 (remaining shoes) = 55.6%.
60% * 55.6% = 33%. Therefore, the chance of drawing two red
shoes is 1/3.
4