There are two candles of equal lengths and of different thickness. The thicker one lasts of six hours. The thinner 2 hours less than the thicker one. Ramesh lights the two candles at the same time. When he went to bed he saw the thicker one is twice the length of the thinner one. How long ago did Ramesh light the two candles .

4 Answers on this Question

1. let x be lenghth of candles.
   thicker one—- in 1 hr 1/6th will go.
   thinner one— in 1 hr 1/4th will go.
   let he lit for n hrs.
   so in n hrs thicker one goes n/6.
   and thinner one goes n/4.
   so remainini length are x-n/6 and x-n/4.so x-n/6=2(x-n/4)
   implie n=3x. if x=1 n=3hrs.

   Reply

2. Hrs Remaining Candle (Thicker) Remaining
   Candle (Thiner)
   Lighted 1 1
   1 0.833333333 0.75
   2 0.666666667 0.5
   3 0.5 0.25 Answer
   4 0.333333333 0
   5 0.166666667
   6 0
   Its clear from above table that the Ramesh light the two
   candles Before 3 Hrs

   Reply

3. Answer 3 hrs
   Hrs Remaining Candle (Thicker) Remaining
   Candle (Thiner)
   Lighted 1 1
   1 0.833333333 0.75
   2 0.666666667 0.5
   3 0.5 0.25 Answer
   4 0.333333333 0
   5 0.166666667
   6 0
   It’s clear from the above table that the Ramesh light the two
   candles Before 3 Hrs

   Reply

4. let x be lenghth of candles.

   thicker one—- in 1 hr 1/6th will go.
   thinner one— in 1 hr 1/4th will go.

   let he lit for n hrs.

   so in n hrs thicker one goes n/6.
   and thinner one goes n/4.

   so remainini length are x-n/6 and x-n/4.so x-n/6=2(x-n/4)
   implie n=3x. if x=1 n=3hrs.

   Reply