There are two candles of equal lengths and of different
thickness. The thicker one lasts of six hours. The thinner
2 hours less than the thicker one. Ramesh lights the two
candles at the same time. When he went to bed he saw the
thicker one is twice the length of the thinner one. How
long ago did Ramesh light the two candles .
let x be lenghth of candles.
thicker one—- in 1 hr 1/6th will go.
thinner one— in 1 hr 1/4th will go.
let he lit for n hrs.
so in n hrs thicker one goes n/6.
and thinner one goes n/4.
so remainini length are x-n/6 and x-n/4.so x-n/6=2(x-n/4)
implie n=3x. if x=1 n=3hrs.
let x be lenghth of candles.
thicker one—- in 1 hr 1/6th will go.
thinner one— in 1 hr 1/4th will go.
let he lit for n hrs.
so in n hrs thicker one goes n/6.
and thinner one goes n/4.
so remainini length are x-n/6 and x-n/4.so x-n/6=2(x-n/4)
implie n=3x. if x=1 n=3hrs.
Hrs Remaining Candle (Thicker) Remaining
Candle (Thiner)
Lighted 1 1
1 0.833333333 0.75
2 0.666666667 0.5
3 0.5 0.25 Answer
4 0.333333333 0
5 0.166666667
6 0
Its clear from above table that the Ramesh light the two
candles Before 3 Hrs
Answer 3 hrs
Hrs Remaining Candle (Thicker) Remaining
Candle (Thiner)
Lighted 1 1
1 0.833333333 0.75
2 0.666666667 0.5
3 0.5 0.25 Answer
4 0.333333333 0
5 0.166666667
6 0
It’s clear from the above table that the Ramesh light the two
candles Before 3 Hrs
let x be lenghth of candles.
thicker one—- in 1 hr 1/6th will go.
thinner one— in 1 hr 1/4th will go.
let he lit for n hrs.
so in n hrs thicker one goes n/6.
and thinner one goes n/4.
so remainini length are x-n/6 and x-n/4.so x-n/6=2(x-n/4)
implie n=3x. if x=1 n=3hrs.