There are two water tanks X andY , X is much smaller than Y. While water fills at the rate of 1 liter every hour in X, it gets filled up like, 10, 20, 40, 80, 160 in tank Y. (At the end of first hour, Y has 10 liters, second hour it has 20 liters and so on). If tank Y is 1/32 filled of the 21 hours, what is total duration of hours required to fill it completely?
1/32(x)L=21h
10L=1h
X=21x10x32
=6720 Liters
Thus:
6720L=Yh
10L=1h
Yh=6720/10
Y=672h