Ques:- Two trains are moving in the same directions at 65 km/hr and 45 km/hr. The faster train crosses a man in slower train in 18 seconds. The length of the faster train is
A. 100 m
B. 120 m
C. 145 m
D. 180 m
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relative speed is=65-45=20kmph, 20*(5/18)=5.5555m/s
time=18sec
distance=speed*time=5.5555*18=100m
100m
65 – 45 = 20 kmph
20 * 5/18 =50/9 m/s
50/9* 18 = 100m/s
65-45km/h=20km/h
D=s*t
therefore 20km/h * 1000 =20000m * 18/3600
20000 * 1/200=100m
100m
Total Distance =?
Time = 18
20 = (X/18) x (18/5) => 100
180
A 100
relative speed is=65-45=20kmph, 20*(5/18)=5.5555m/s
time=18sec
distance=speed*time=5.5555*18=100m
Assuming 1st train length is = X mtr.
Relative speed of both train will be = (65-45)*5/18 = 100/18 Km/Hrs.
1st train taking time to crossing the boy sitting in slower train is = 18 sec.
Then equation will be :
Distance = (Relative Speed) * (total taken Time)
X = (20*5/18) * (18)
Then Train distance (X) = 100 Mtrs.
Good
100
100meter
65 faster train
45 slower train
faster train crosses slower one by 20 kmph
and if it crosses the slower one in 18 sec then the length of faster train is
20*1000*18/3600
100m
so the length of the faster train is 100m
20*1000*18/3600
360000/3600
100
100m/s
100 metres
100m
A man in slower train ;speed =45 km/h
Faster train speed = 65 km/h
crossed speed is =difference of speed = 65km/h – 45 km/h = 20 km/h
Length of train = (20 *18)/3600=0.1 km = 0.1*1000=100 meter
Relative speed =65-45km/hr
Relative speed=20km/hr
Convert to m/s
S=20*5/18
S=5.555
Length of the faster train =5.55555*18seconds
=100meters