A can swim & cross 50m(the length of swimming pool) in 2 min. B can swim & cross 50m in 2min 15sec. Every time when they meet a bell gong is struck. For 2000m how many bell sounds might be produced?
A swims 50mts in 2mins*60=120secs;
B swims 50mts in 2.15mins*60=135secs;
To swim 2000mts, 50mts*40times=2000mts;
so A swims for 120secs*40times=4800secs;
so B swims for 135secs*40times=5400secs;
The common factor for 120secs,135secs is 1080secs.
For A, 4800secs/1080secs=4.4(app 4)
For B, 5400secs/1080secs=5
Therefore A and B meet 4 times and hence bell will struck 4
times………..
A swims 50mts in 2mins*60=120secs;
B swims 50mts in 2.15mins*60=135secs;
To swim 2000mts, 50mts*40times=2000mts;
so A swims for 120secs*40times=4800secs;
so B swims for 135secs*40times=5400secs;
The common factor for 120secs,135secs is 1080secs.
For A, 4800secs/1080secs=4.4(app 4)
For B, 5400secs/1080secs=5
Therefore A and B meet 4 times and hence bell will struck 4
times………..
If the bell rung when they r started is also counted then it
will be 5 otherwise 4