A cow is tethered in the middle of a field with a 14 feetlong rope. If the cow grazes 100 sq feet per dayapproximately. What time will be taken by the cow to grazethe grazeable area of the field?

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1. ( d ) 6 days

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2. area consumed = pi*14*14 = 615.44 sq.ft
   rate of consumption = 100sq.ft per day
   No of days = 615.44/100=6.1
   rounding off to 6 days approx..
   (not sure)

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