Ques:- A train 280 m long is moving at 60 km/hr. Time taken by the train to cross a tunnel 220 m long is
A. 15 sec
B. 20 sec
C. 25 sec
D. 30 sec
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30sec
30sec
Can anyone provide the solution ?
Total distance = ( 280 m + 220 m) = 500 m ; speed = 60 km/hr = 16.2 m/s ( convert km/hr to m/s {i.e multiple 60 by 5/18} )
speed = distance/ time
time = d/s = 500/16.2 = 30 s
Time = Distance/Speed
Total Distance = (280+220) = 500 m
Speed = 60 km/hr = 60*(5/18) m/s = 50/3 m/s
Time = 500/(50/3) = 1500/50 = 30 Sec.
Answer = 30 sec.
convert 60 km/hr into m/s.
we get (50/3)m/s.
now the total distance is 280m+220m = 500m
NOW APPLY THE FORMULA FOR GETTING THE TIME IS
S = D/T
T =D/S
T =( 500M) / (50/3) =30 seconds.
280m+220m=500m
280m for 60km/hrs.
60km/hr=16.7m/s.
Time taken for 500m to travel for 16.7m/s
500/16.7=30s
60 km/hr
60×5/18=50/3m/see
50/3 m cover 1 sec
So,500 m cover= (3/50)*500
=30 sec
Ans= 30 sec
Time = Distance/Speed
Total Distance = (280+220) = 500 m
Speed = 60 km/hr = 60*(5/18) m/s = 50/3 m/s
Time = 500/(50/3) = 1500/50 = 30 Sec.
Answer = 30 sec.
Correct option is D)
Distance=(280+220)m=500m
Speed=60 km/hr=>60×0.27=16.2
Then
By Speed Formula:speed =distance/time
Time=distance/speed
Then
Time=500/16.2=30s
Train 1st move dist. 280m at time is 60kmph.
Speed 1= d/t =280/60*5/18 = 17.2
Train to cross tunnel length. 220m at a time 60kmph.
Speed 2=d/t =220/60*5/18 = 13.5
Total time taken by the train =speed 1 + speed 2
=17.2+13.5 = ~30.7sec
I think,30sec is a answer.
Distance=(280+220)m=500m
Speed=60 km/hr=60× (5/18)m/sec=(50/3)m/sec
Time=500/(50/3)sec=30 sec
60 = 500×3600/tx1000
t = 30s
280+220/60*(5/18)=(500/60*5)*18=30
D = 280 + 220 = 500
S = 60 * 5/18 = 16.66
T = D/S = 500/16.66
T = 30S
30 Sec