2 men r playing tossing a coin. If one of them wins he gets 1$ from the loser. At the end of a no. of games, one of them had lost 3$ and the other won 3 times. How many games did they play?

One Answer on this Question

1. Let and A and B are playing and A has 3$ and B won 3 times.

   Total money earn by A = no of games A won – no of games A loss
   if A loss game means B won.
   Therefore
   Total money earn by A = no of games A won – no of games B won
   3 = no of games A won -3
   no of games A won=6
   So
   A won = 6 games
   B won = 3 games

   Hence total no of games is 9

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