Cost of an item is x. It’s value increases by p% and decreases by p% Now the new value is 1 rupee, what is the actual value ?

2 Answers on this Question

1. original cost is 100^2 / (100^2 – p^2) Rs

   Reply

2. Let the item cost be I then,
   Item cost by increasing p% will be:
   I(100+p)/100
   Item Cost by decreasing p% will be:
   I(100+p)(100-p)/100*100
   But the above is equal to 1.
   So,
   I(100^2-p^2)/100^2 = 1 => I = 100^2/(100^2 – p^2).

   Reply