for a number to be divisible by 4, last two digits must be
divisble by 4.
so 32,36,72,76 are the only for possible combinations at
the last two positions.
The first position can be filled in 4 ways and similarly
second position also can be filled in 4 ways. so totally in
4*4=16 way for filling firt two positions.
So totally 16+4=20 distinct numbers can be formed
Ans = 8
Use simple box method
[1][2][2][2]= 1x2x2x2 =8
Logic >
once place have 2 number (2,6)
Tens place have also 2 number (7,3)
So that number is divisible by 4
Now, 2 numbers fixed at once and tens place left 2 numbers which is choice at hundredth place
Now 3 number fix left 1 number which is placed at thousands place
Total number form is 4×4 = 16
But divisible by 4 is 1x2x2x2 =8
possible number is 8.
numbers are
3276,2376,7632,6732,6372,3672,7236,2736
these r possible number.
for a number to be divisible by 4, last two digits must be
divisble by 4.
so 32,36,72,76 are the only for possible combinations at
the last two positions.
The first position can be filled in 4 ways and similarly
second position also can be filled in 4 ways. so totally in
4*4=16 way for filling firt two positions.
So totally 16+4=20 distinct numbers can be formed
Ans = 8
Use simple box method
[1][2][2][2]= 1x2x2x2 =8
Logic >
once place have 2 number (2,6)
Tens place have also 2 number (7,3)
So that number is divisible by 4
Now, 2 numbers fixed at once and tens place left 2 numbers which is choice at hundredth place
Now 3 number fix left 1 number which is placed at thousands place
Total number form is 4×4 = 16
But divisible by 4 is 1x2x2x2 =8