Find the four digit number in which the first digit is 1/3 of the second, the third is the sum of the first and second, and the last is three times the second.

One Answer on this Question

1. let the 4 digit number be ABCD.
   First Digit is A :
   Therefore; according to the question
   A=B/3
   B=3A
   C=A+B=A+3A=4A
   D=3B=3(3A)=9A
   Since the last Digit is D and it can neither be double-digit nor 0 ;
   Therefore ;
   A=1;
   B=3A=3(1)=3
   C=A+B=1+3=4
   D=9A=9(1)=9
   Therefore, the 4 digit number is 1349.

   Reply