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14=2*7
10=2*10
Hcf=2
Lcm=2*7*5=70
2a × 2b = 2 × 70
4 ab = 140
ab = 140/4
ab = 35
a×b = 5 × 7
therefore a = 5 , b= 7
now
we know that
2a × 2b
2 × 5 , 2 × 7
= 10 , 14
Let the numbers be x and y.
xy = HCF*LCM = 140
x+y = 24
Solving, x(24-x) = 140
=x²-24x+140 = 0
x =>10 or 14
If x=10, y=14
d
HCF= 2
LCM = 2*5*7 = 70