The difference between a two-digit number and the number obtained by interchanging the digits is 36. What is the difference between the sum and the difference of the digits of the number if the ratio between the digits of the number is 1 : 2 ?

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1. The number is greater than the number obtained in reversing the digits and the ten’s digit is greater than the unit’s digit
   Let ten’s and unit’s digit be 2x and x respectively
   Then, (10×2x+x)−(10x+2x)=36
   9x=36
   x=4
   Required difference=(2x+x)−(2x−x)=2x=8

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