there are 27 coins in which 0ne is heavier than rest(all equal weight).how many measurements are needed to isolate that odd one.

3 Answers on this Question

1. Three Measurements.
   Take three Divisions each
   9 9 9 Odd one goes out in First Measurement
   Again take three divisions
   3 3 3 Odd one goes out in Second Measurement
   Again take three divisions
   1 1 1 Odd one comes into ur hand in Third
   Measurement

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   1. If division of 3 is allowed then I might do 5 divisions in one go & do in less iterations. I would assume max 2 division as you have to hands, and compare the weight.

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2. four measurement
   take 13 coins(26 coins) in each hand
   wt is equal then 27 th coin has heavier wt
   else
   take 6 coins(12 coins) in each hand-which has more wt
   wt is equal then 13 th coin has heavier wt
   else
   take 3 coins(6 coins) in each hand-which has more wt
   take 1 coins(2 coins) in each hand-which has more wt
   wt is equal then 3rd coin has heavier wt

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