A is travelling at 50kmph, B is travelling at 40
kmph……..according to the formula
time taken to meet = distance between them
———————-
relative speed of two vehicles
so, time taken to meet= 15/(50-40)=15/10=3/2hrs
lets say car A is travelling at 50Kmph and Car B at 40 Kmph.
Since the question is not very clear, we have two
possibilities. That the cars are either travelling in same
direction or they are travelling in opposit directions.
If the cars are travelling in the same direction then again
there are two possibilities
First: Car B is behind Car A – then the cars will never
meet.
Second: Car A is behind Car B then they will meet after 90
mins (one and a half hour) Car B travells 60 Kms in 90 mins
and Car A travells 75 Kms in 90 mins. Car A is 15 Kms
behind Car B so it has to cover those 15 Kms in the same
time to reach car B which is 60+15 = 75 kms.
If the cars are travelling in the opposite direction then
they will meet in approximately 10 minutes. this can be
calculated as follows.
let us say they meet at a point X as shown below
A ———————–X—————-B
—-> 15-X <--- ! ----> X <----
since both travel for the same amount of time let the time
taken be T hours.(since the speed is in KMPH time taken
will be calculated in hours)
From the above B has to travel X Kms and A the remaining
distance which is 15-X kms ( Distance between A & B is
15Kms)
From the formula Distance = Speed * Time we can say
Time = Distance / Speed
Hence T(A) = (15-X)/50 _______ Eq 1
and T(B) = X/40 __________ Eq 2
Since T(A) = T(B),
we have (15-X)/50 = X/40 ______Eq 3
By solving the above Eq 3 we get X = 6.666 Kms
Substituting X in either of Eq 1 or Eq 2
we get T = 0.1666 Hrs which is approximately 10 Mins.
A is travelling at 50kmph, B is travelling at 40
kmph……..according to the formula
time taken to meet = distance between them
———————-
relative speed of two vehicles
so, time taken to meet= 15/(50-40)=15/10=3/2hrs
lets say car A is travelling at 50Kmph and Car B at 40 Kmph.
Since the question is not very clear, we have two
possibilities. That the cars are either travelling in same
direction or they are travelling in opposit directions.
If the cars are travelling in the same direction then again
there are two possibilities
First: Car B is behind Car A – then the cars will never
meet.
Second: Car A is behind Car B then they will meet after 90
mins (one and a half hour) Car B travells 60 Kms in 90 mins
and Car A travells 75 Kms in 90 mins. Car A is 15 Kms
behind Car B so it has to cover those 15 Kms in the same
time to reach car B which is 60+15 = 75 kms.
If the cars are travelling in the opposite direction then
they will meet in approximately 10 minutes. this can be
calculated as follows.
let us say they meet at a point X as shown below
A ———————–X—————-B
—-> 15-X <--- ! ----> X <---- since both travel for the same amount of time let the time taken be T hours.(since the speed is in KMPH time taken will be calculated in hours) From the above B has to travel X Kms and A the remaining distance which is 15-X kms ( Distance between A & B is 15Kms) From the formula Distance = Speed * Time we can say Time = Distance / Speed Hence T(A) = (15-X)/50 _______ Eq 1 and T(B) = X/40 __________ Eq 2 Since T(A) = T(B), we have (15-X)/50 = X/40 ______Eq 3 By solving the above Eq 3 we get X = 6.666 Kms Substituting X in either of Eq 1 or Eq 2 we get T = 0.1666 Hrs which is approximately 10 Mins.