Two trains starting at same time, one from Bangalore to Mysore and other in opposite direction arrive at their destination 1 hr and 4 hours respectively after passing each other.How nuch faster is one train from other?

2 Answers on this Question

1. Its 2 times faster than the other train
   v1*t=v2
   v2*t=4*v1
   solving these two,we get
   v2/v1=2

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2. et v1-peed of train from bangalore to mysore(train1)
   v2- speed of train from mysore to bangalore(train2)
   and x be the distance from B to M
   and a be the distance from bangalore till meet point
   (i.e.)train1 travels a km and train2 travels x-a km
   time taken by train1 to travel a=time taken by train2 to
   travel x-a
   a/v1=x-a/v2, v1/v2=a/x-a
   time taken by train1 to travel x-a=1hr
   x-a/v1=1, x-a=v1
   time taken by train2 to travel a=4hrs
   a/v2=4, a=4v2
   therefore s1/s2=4s2/s1
   s1^2=4s2^2
   s1:s2=2:1
   train1 speed=twice the speed of train2

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